请教一个字符串替换的问题

This topic created in 4438 days ago, the information mentioned may be changed or developed.

字符串：
variant of 紙|纸[zhi3]; paper;

我想把紙|纸[zhi3] 中|之前和[之后的内容删除，只保留 “纸”，并以"纸"为参数添加链接，最终得到类似下面的这种
variant of <a href='search?id=纸'>纸; paper;

请问用PHP或者JS怎么做？现在想到的是按照;拆分，然后在按照空格拆分，判断是否有|出现，有的话，执行查找、替换，有更简便的办法吗？

谢谢

zhi3

variant

Paper

5 replies • 1970-01-01 08:00:00 +08:00

casparchen

Apr 13, 2014

为嘛不正则式

JoyNeop

Apr 14, 2014

var a1 = raw.slice(0, raw.indexOf('[')) + raw.slice(raw.indexOf(']') + 1)
var zhi = raw.slice(13, 14)
var paper = raw.slice(raw.indexOf(';') + 1)
var out = 'variant of <a href="search?id=' + zhi + '">' + zhi + '; ' + paper + '</a>'

Mutoo

Apr 14, 2014

var str = "variant of 紙|纸[zhi3]; paper;";
var zhi = str.split(" ")[2].split("|")[1].split(/[\[\]]/)[0];
var paper = str.split(" ")[3].split(";")[0];

y051313

Apr 14, 2014

@JoyNeop
@Mutoo
已发送感谢。多谢了

JoyNeop

Apr 14, 2014 via iPad

@Mutoo 这点小事也上正则囧丁乙……