int64ago

Hacker News: A Javascript journey with only six characters

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  •   int64ago · Oct 9, 2016 · 2325 views
    This topic created in 3528 days ago, the information mentioned may be changed or developed.

    原文

    先执行下面的代码 :-)

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    8 replies    2016-10-09 22:27:08 +08:00
    goofansu
        1
    goofansu  
       Oct 9, 2016 via iPhone
    javascript 博大精深啊
    shiji
        2
    shiji  
       Oct 9, 2016
    乌云很早就提过,标题是: jother 编码之谜

    另外还有一个叫 JSfuck 的,也有类似的功能。

    最后附赠一份清单:
    http://www.evil0x.com/posts/27318.html
    CYKun
        3
    CYKun  
       Oct 9, 2016 via Android
    javascript 里类似 []+[]==="" 这样的行为是语言规范定义的吗?是的话不是显得很奇怪吗。。
    est
        4
    est  
       Oct 9, 2016
    当年在 slackers 上那个神贴一步一步看众大神把字符逐渐精简到 6 字符的路过。
    reallarry
        5
    reallarry  
       Oct 9, 2016 via Android
    wtf
    Busy
        6
    Busy  
       Oct 9, 2016
    每次看到类似的,都觉得很作
    noe132
        7
    noe132  
       Oct 9, 2016   ❤️ 1
    @CYKun
    语言规范定义了。
    两个值用+操作符,首先要转化成原始值类型,用到里内部函数 ToPrimitive 。
    这种情况下对象转化为原始值类型调用对象 toString()方法 或 ValueOf()方法。
    http://www.ecma-international.org/ecma-262/7.0/index.html#sec-addition-operator-plus

    []的 toString 继承自 Array.prototype.toString ,方法的定义在
    http://www.ecma-international.org/ecma-262/7.0/index.html#sec-array.prototype.tostring

    Let array be ? ToObject(this value).
    Let func be ? Get(array, "join").
    If IsCallable(func) is false, let func be the intrinsic function %ObjProto_toString%.
    Return ? Call(func, array).

    意思就是返回调用 join 方法的值
    空数组[].join()的值就是 ""

    所以[]+[] === ""在 runtime 时处理的操作就是讲两个空数组转换为原始值类型相加,再与右边比较
    CYKun
        8
    CYKun  
       Oct 9, 2016
    @noe132 这规范颇有点先打一枪再画靶子的味道 : )
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